Question: What is the unit normal of the triangle with vertices (-1, 0, 0)
, (1, 0, 0)
, (0, 1, 0)
?
Answer: Notice that the triangle lies entirely in the XY plane. Therefore the unit triangle normal, or the normal which is perpendicular to the plane containing the triangle, is (0, 0, 1)
, or simply the "up" (Z) vector.
(1, 1, 0)
and (0, 0, 1)
(YES: 1*0 + 1*0 + 0*1 = 0)
(-1, 1, 0)
and (1, -1, 0)
(NO: -1*1 + 1*-1 + 0*0 = -2)
(-2, 1, 0)
and (1, 2, 0)
(YES: -2*1 + 1*2 + 0*0 = 0)
(1, 2, 1)
and (-3, 1, 1)
(YES: 1*-3 + 2*1 + 1*1 = 0)
(1, 1, 3)
onto the vector (1, 1, 1)
? (5/3, 5/3, 5/3)
(2, 1)
(NO)(1, 0)
(YES)(0, 3)
(NO)What is this saying in English? We will talk about Fourier Transforms more in the second unit of the course, but they are basically a way of breaking down a function into a bunch of periodic components. They are useful for anlayzing sound, for example, because musical instruments and voices resonate at particular frequencies, and it's easier to see what's going on when we put on our "frequency glasses."
Now how about the Fourier transform of the function in this question? A "delta function" is a function which is a "unit impulse." It's a function that is zero everywhere except at the origin, where it is infinity (I'm glossing over some technical properties here..it's actually a "distribution" not a function). Anyway, for an example of something in nature that's like a delta function, think of a balloon popping. Assuming there are no echoes, it's quiet right before the balloon pop and quiet right after, but there is a very loud sound at the instant that the balloon pops. It turns out that if we look at the fourier transform of such a signal, it has the same amount of all energy at all frequencies. And in particular for a unit impulse delta that occurs at the origin, the all frequencies have a magnitude of 1 with phase zero.
If this seems like nonsense now, don't worry, we'll talk about it later, and you'll get some intuition before we do on the first group assignment on sound rendering